The Trigonometric ratios of angle π/2 θ Thinking of θ as an acute angle (that ends in the 1st Quadrant), (π/2θ) or (90°θ) ends in the 2nd Quadrant where only sine of the angle is positive The (π/2θ) formulas are similar to the (π/2θ) formulas except only sine is positive because (π/2θ) ends in the 2nd Quadrant sin(π/2θ) = cosθCosθ1 sinθ = sinπ2 θ1 cosπ2 θ = 2sinπ4 θ2cosπ4 θ22 cos2π4 θ2 = sinπ4 θ2cosπ4 θ2 = tanπ4 θ2Cosθ =5/13 with π/2 < θ 96 results Pre Calculus Let θ be an angle in quadrant IV such that cosθ = 4/9 Find the exact values of csc θ and cot θ If cosθ cos^2 θ = 1, then sin^12 θ 3 sin^10 θ 3 sin^8 θ sin^6 θ 2 sin^4 θ 2 sin^2 θ – 2 =?
If Pi 2 Lt Theta Lt 3pi 2 Then Sqrt Tan 2 Theta Sin 2 Theta Is Equal To
